({left( {2x - 1} right)^2} - 25 = 0)
Giải chi tiết:
({left( {2x - 1} right)^2} - 25 = 0)
(begin{array}{l},,,,,,,,{left( {2x - 1} right)^2} - 25 = 0\ Leftrightarrow {left( {2x - 1} right)^2} - {5^2} = 0\left( { Leftrightarrow 2x - 6} right)left( {2x + 4} right) = 0\ Leftrightarrow left[ begin{array}{l}2x - 6 = 0\2x + 4 = 0end{array} right. Leftrightarrow left[ begin{array}{l}x = 3\x = - 2end{array} right.end{array})
Vậy (x in left{ { - 2;,,3} right}).